j
k
j a
j l
… or I’d probably simply listen to Hans-Jürgen ;)
On Thu, Jun 30, 2022 at 5:32 PM Christian Grün christian.gruen@gmail.com wrote:
I’d probably do this: count($step/preceding-sibling::*) + 1
I’d probably do this:
count($step/preceding-sibling::*) + 1
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