I was going to ask if I could count on the difference always being in a PxxxD format. I am happy to see that days-from-duration doesn't return 0. I tried casting the xs:duration to many formats and kept getting 0.

Thanks for the tips

On Fri, Dec 6, 2019 at 11:38 AM Christian Grün <christian.gruen@gmail.com> wrote:
Hi France,

The function fn:years-from-duration is fairly basic; it only returns
the year component of your duration argument (as xs:dayTimeDuration
has none, in contrast to xs:yearMonthDuration). The background: A year
may have 365 or 366 days, and the duration is not sufficient to
compute the number of years.

You can use the average number of years for your computation if that’s
sufficient for your use case (see [1] for a variety of approximations
to choose from):

  let $d1 := xs:date('2007-07-31')
  let $d2 := xs:date('2019-12-06')
  let $duration := $d2 - $d1
  let $days := days-from-duration($duration)
  return $days div 365.2425

Best,
Christian

[1] https://en.wikipedia.org/wiki/Year



On Fri, Dec 6, 2019 at 11:24 AM France Baril
<france.baril@architextus.com> wrote:
>
> Hi,
>
> The following function returns P4511D: 0 but I expect P4511D: 12
> Bug or bad usage?
>
>> let $d1 := xs:date('2007-07-31')
>> let $d2 := xs:date('2019-12-06')
>> let $duration := $d2 - $d1
>> let $years := years-from-duration($duration)
>> return $duration || ': ' || $years


--
France Baril
Architecte documentaire / Documentation architect
france.baril@architextus.com