Hi Rob,

here's yet another solution:

  let $path := "Q{http://www.w3.org/2005/xpath-functions}root()/Q{}A[1]/Q{}B[1]/Q{}C[1]/Q{}D[1]"
  return analyze-string($path, '(Q\{.*?\}.*?)(/|$)')/fn:match/fn:group[1]/string()

> @Christian: On the other hand I can imagine that within Basex the path-expression is built from these elementary steps.

> If so, is it in any way possibly to retrieve this elementary steps sequence instead of this path-expression?


Currently, there is no other way to retrieve paths, so you'll have to manually split the path as indicated above..

Christian



On Wed, Oct 8, 2014 at 2:10 PM, Marco Lettere <marco.lettere@dedalus.eu> wrote:
Hi Rob,
don't know whether your prefix is constant.

If it is then

let $prefix := "Q{http://www.w3.org/2005/xpath-functions}root()"
let $inpstr := "Q{http://www.w3.org/2005/xpath-functions}root()/Q{}A[1]/Q{}B[1]/Q{}C[1]/Q{}D[1]"
return ($prefix,
        tokenize(substring-after($inpstr, $prefix),"/"))

should do the job.
M.


On 08/10/2014 13:37, Rob Stapper wrote:

Hi,

 

Basically I want to break down the path-expression of a node in my XML into its elementary steps.

QName: “Q{http://www.w3.org/2005/xpath-functions}root()/Q{}A[1]/Q{}B[1]/Q{}C[1]/Q{}D[1]” must become QName-sequence: (“Q{http://www.w3.org/2005/xpath-functions}root()”, ”Q{}A[1] ”, ”Q{}B[1] ”, ”Q{}C[1] ”, ”Q{}D[1]”)

 

So I need to break the path-expression down on the “/”-characters which aren’t part of the namespace-uries.

 

I’m using the “fn:tokenize”-function for this. The function uses a “regular expression” for it’s separator.

Unfortunately my regex-experience is zero (well, two days by now). I came up with the next brilliant ;-) solution:  fn:tokenize( path( $node), “/(?=Q)”).

Again, unfortunately, this doesn’t work because the xquery-flavor of regex doesn’t support looking around.

Sure, I can use “/Q” as pattern and subsequently  stick a “Q” in front of every substring (except the first one) but I’m looking for  a solid solution.

 

I there anyone out there with enough “regex-for-xquery”- experience to help me with this?

Big thanx for that in advance.

 

@Christian: On the other hand I can imagine that within Basex the path-expression is built from these elementary steps.

If so, is it in any way possibly to retrieve this elementary steps sequence instead of this path-expression?

 

Thanx,

 

Rob Stapper




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