Marc,
I’ve solved the issue in another way but thanks anyway for the code snippet.
Rob.
Van: Marc van Grootel [mailto:marc.van.grootel@gmail.com]
Verzonden: vrijdag 15 augustus 2014 12:50
Aan: Rob Stapper
CC: BaseX
Onderwerp: Re: [basex-talk] relative path between two element in xquery
Hey Rob,
In my lib I have a function that protects all regexp special characters.
Maybe a bit too much heavy machinery for what it does but it works ;-)
I gladly receive improvements.
declare function route:re-escape($string as xs:string)
as xs:string {
let $regexp-chars := ('.','*','+','|','?','(',')','[',']','{','}','^')
return
(: Note that '\' and '$' in the fold caused invalid pattern errors therefore put them in separate replace :)
fold-left(
$regexp-chars,
replace(replace($string, '\\', '\\\\'), '\$', '\\\$'),
function($a, $b) {
replace($a, '\'||$b, '\\'||$b )
}
)
};
--Marc
On Fri, Aug 15, 2014 at 11:55 AM, Rob Stapper <r.stapper@lijbrandt.nl> wrote:
Hi,
How can I construct the relative path between two elements in an xml-file.
Most probably overlooking the obvious I ended up with the solution below, which, unfortunately, triggers an runtime-error.
My not-working solution:
let $xml :=
<xml>
<A>
<B/>
</A>
</xml>
let $b := $xml//B
let $a := $xml//A
return replace( string( path( $b))
, string( path( $a))
, ''
)
Two questions:
- How to retrieve the relative path between two element within a xml-file?
- Why does the solution above trigger an error? Can it be a bug? ( oops, three questions)
Thnx in advance for the reply,
Rob Stapper
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--
--Marc
