Hi Martin,
What I was looking for is a “quick way” to get a comparison such that an item (when it is repeated more than once) is returned only as many times as it appears in both sequences. For example, in
for $a in (1,2,3,5,3,3) where $a = (1,3,2,3, 2) group by $k := $a return <c>{$a}</c>
you get
<c>1</c> <c>2</c> <c>3 3 3</c>
with three 3 even if in the second sequence you have two 3.
On 26. Nov 2020, at 08:30, Martin Honnen martin.honnen@gmx.de wrote:
Am 26.11.2020 um 07:14 schrieb Martin Honnen:
My bad, use group by $k := $a return <c>{$a}</c>
To describe it clearer, the whole FLOWR should be
for $a in (1,2,3,5) where $a = (1,3,2,3) group by $k := $a return <c>{$a}</c>