> Any chance this could be made an option of map:merge? Doing it in Java would
> be faster and more elegant.

It will be too late for XQuery 3.1, but feel free to motivate such
enhancements in the W3 Bug Tracker [1].

Christian

[1] https://www.w3.org/Bugs/Public/

>
> Best,
> Ron
>
> On December 29, 2015 at 3:12:28 AM, Christian Grün
> (christian.gruen@gmail.com) wrote:
>
> Try this:
>
> let $maps := (
> map:entry(0, "red"),
> map:entry(1, "green"),
> map:entry(1, "blue")
> )
> return map:merge(
> for $map in $maps
> for $key in map:keys($map)
> group by $key
> return map { $key : $map ! .($key) }
> )
>
> This is an equivalent, possibly better readable, solution:
>
> let $maps := (
> map:entry(0, "red"),
> map:entry(1, "green"),
> map:entry(1, "blue")
> )
> let $keys := distinct-values(
> for $map in $maps
> return map:keys($map)
> )
> return map:merge(
> for $key in $keys
> let $value :=
> for $map in $maps
> return $map($key)
> return map { $key : $value }
> )
>
>
> On Wed, Dec 23, 2015 at 11:04 PM, Ron Katriel <rkatriel@mdsol.com> wrote:
>> Hi,
>>
>> I am using map:merge to construct a map from smaller maps and would like
>> to
>> preserve values when keys agree. For example, when calling
>>
>> map:merge((map:entry(0, "red"), (map:entry(1, "green"), map:entry(1,
>> "blue")))
>>
>> I would like to get back something like
>>
>> map { 0: "red", 1: ("green", "blue") }
>>
>> The default (W3C) behavior is to drop "green" in favor of "blue".
>>
>> Is there a simple way to accomplish this? I realize the above example is
>> mixing types so presumably a solution would have all values as sets.
>>
>> Thanks,
>> Ron
>>