29 Jul
2015
29 Jul
'15
11:42 a.m.
Hi,
That would base the type annotation on the lexical value. For instance, the string '0' would be labelled as "integer" (given you test for xs:integer before xs:string):
let $var := '0' return if ( $var castable as xs:integer ) then 'integer' else if ( $var castable as xs:string ) then 'string' else 'unknown type' (: -> 'integer' :)
The operator "instance of" would solve that problem. But then, for that purpose, there is the "typeswitch" instruction:
typeswitch ( '0' ) case xs:integer return 'integer' case xs:string return 'string' default return 'unknown type' (: -> 'string' :)
Regards,
--
Florent Georges
http://fgeorges.org/
http://h2oconsulting.be/
On 29 July 2015 at 17:34, Eliot Kimber ekimber@contrext.com wrote:
> I believe you need to use the "castable as" or "instance of" operators to
> determine the type, e.g.:
>
> let $typeName :=
> if ($somevar castable as xs:integer)
> then 'integer'
> else if ($somevar castable as xs:string)
> then 'string'
> else 'unknown type'
>
> Or something close to that. There is also "instance of", which might be
>
> I also found this paper, which might be interesting:
>
> http://www.balisage.net/Proceedings/vol8/html/Holstege01/BalisageVol8-Holst
> ege01.html
>
> Cheers,
>
> E.
> ----
> Eliot Kimber, Owner
> Contrext, LLC
> http://contrext.com
>
>
>
>
> On 7/29/15, 9:54 AM, "Rob Stapper"
> <basex-talk-bounces@mailman.uni-konstanz.de on behalf of
> r.stapper@lijbrandt.nl> wrote:
>
>>Hello,
>>
>>I must be overlooking something, so excuses in advance, but: How can I
>>retrieve the datatype of a variable?
>>
>>TIA,
>>Rob Stapper
>>
>>
>>
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