Hi Yitzhak,
Try this:
declare context item := document { ... }; * update { delete node employee }
See [1] for more information on updating expressions.
Best, Christian
[1] https://docs.basex.org/wiki/XQuery_Update
On 9/13/20, Yitzhak Khabinsky ykhabins@bellsouth.net wrote:
Hello,
This is input XML:
<employee emp="1" dept="55"> <name>Peter</name> <job>Director</job> <employee emp="12" dept="26"> <name>John</name> <job>Animator</job> <employee emp="123" dept="27"> <name>James</name> <job>Assistant</job> </employee> </employee> </employee>
Desired output XML:
<employee emp="1" dept="55"> <name>Peter</name> <job>Director</job> </employee>
Overall, it is a so called 'modified identity transformation' in XSLT parlance.
Output XML shall be the same, except the child <employee> element and its children.
Question:
What is the best way to re-create existing root element with all its attributes?
My implementation:
xquery version "3.1";
declare context item := document {
<employee emp="1" dept="55">
<name>Peter</name> <job>Director</job> <employee emp="12" dept="26"> <name>John</name> <job>Animator</job> <employee emp="123" dept="27"> <name>James</name> <job>Assistant</job> </employee> </employee></employee>
};
(: working version :)
element {fn:node-name(/*)}
{
let $y := ./*/@*
return $y, (: copy all attributes :)
for $x in ./*/(* except employee)
return $x
}
(: NOT working version, trying to make it more concise :)
element {fn:node-name(/*)} {/*/@*}
{
return for $x in ./*/(* except employee)
return $x
}
Regards, Yitzhak Khabinsky