Hello all,

  I have two resources at the same path in a database.

  XQUERY db:list("project1")

  Returns :

  resultset1.xml

  resultset1.xml

  The two resources have different contents.

  However, when I do the following, I get the XML content from the first file.

  XQUERY db:open("project1", "resultset1.xml") 

 

  What is the way to get the second XML file?

Thanks for your help.

Anupam