Thanks. What happens if you specify BaseX73.jar in the classpath?
java -cp saxon9he.jar;BaseX73.jar org.basex.BaseXGUI ___________________________
On Thu, Sep 13, 2012 at 3:53 PM, Alex Muir alex.g.muir@gmail.com wrote:
Java is being used
On Thu, Sep 13, 2012 at 9:51 AM, Christian Grün christian.gruen@gmail.com wrote:
Dear Alex,
as Max stated, it would be interesting to know what xslt:processor() gives you as result. This way, we will know if Saxon or Java is used as processor.
Thanks, Christian ___________________________
On Thu, Sep 13, 2012 at 3:47 PM, Alex Muir alex.g.muir@gmail.com wrote:
As I said in the first line of my post I'm looking at that module page. The page states that
"XSLT 2.0 is used instead if Version 9.x of the Saxon XSLT Processor (saxon9he.jar, saxon9pe.jar, saxon9ee.jar) is found in the classpath."
I'm launching basex as follows
java -classpath /mnt/xslt_volume/i4EnrichV7/resources/libs/saxon9he.jar -jar /mnt/xslt_volume/i4EnrichV7/resources/libs/BaseX73.jar
Is there anything else I need to do?
On Thu, Sep 13, 2012 at 8:57 AM, Maximilian Gärber gaerber@axxepta.de wrote:
Hi,
did you check http://docs.basex.org/wiki/XSLT_Module ?
using xslt:processor() you can output if you're really using Saxon.
Regards, Max
2012/9/13 Alex Muir alex.g.muir@gmail.com:
Hi,
Following the http://docs.basex.org/wiki/XSLT_Module
I'm launching basex as follows
java -classpath /mnt/xslt_volume/i4EnrichV7/resources/libs/saxon9he.jar -jar /mnt/xslt_volume/i4EnrichV7/resources/libs/BaseX73.jar
I get an error thought when executing which makes me think I have not convinced basex that saxon is there to use...
Error: Stopped at line 14, column 48 in /mnt/xslt_volume/i4EnrichV7/analysis/xquery/AggregateSectionsTitleNormalized.xq: [XPST0017] Unknown function 'current-grouping-key(...)'.
Query: let $in := .//section let $sections :=
<sections> $in </sections> let $style := <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions" xmlns:mh="http://www.metaheuristica.com" version="2.0"> <xsl:output method="xml" indent="no"/>
<xsl:template match="sections"> <groups> <xsl:for-each-group select="section" group-by="@titleNormalized"> <group name="{current-grouping-key()}" count="{count(current-group())}"/> </xsl:for-each-group> </groups> </xsl:template>
</xsl:stylesheet>
return xslt:transform($sections, $style)
What am I doing wrong? Regards
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Alex G. Muir Software Engineering Consultant Linkedin Profile : http://ca.linkedin.com/pub/alex-muir/36/ab7/125 _______________________________________________ BaseX-Talk mailing list BaseX-Talk@mailman.uni-konstanz.de https://mailman.uni-konstanz.de/mailman/listinfo/basex-talk
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Maximilian Gärber
axxepta solutions GmbH Postfach 51 02 38 13362 Berlin
Tel +49 (0)30 499 147 66 Fax +49 (0)30 499 147 67 Mail gaerber@axxepta.de _______________________________________________ BaseX-Talk mailing list BaseX-Talk@mailman.uni-konstanz.de https://mailman.uni-konstanz.de/mailman/listinfo/basex-talk
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Alex G. Muir Software Engineering Consultant Linkedin Profile : http://ca.linkedin.com/pub/alex-muir/36/ab7/125 _______________________________________________ BaseX-Talk mailing list BaseX-Talk@mailman.uni-konstanz.de https://mailman.uni-konstanz.de/mailman/listinfo/basex-talk
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Alex G. Muir Software Engineering Consultant Linkedin Profile : http://ca.linkedin.com/pub/alex-muir/36/ab7/125