Hi Sony,
your problems mostly come down to some syntax mistakes:
(line 22): There's a comma missing between the two for-loops of your modify clause (the query editor in BaseX actually shows you the exact position of the error - I always use it myself when formulating queries).
(line 27) After fixing this the parser comes across an unknown variable, due to a missing underscore.
(line27) Fixing this there's another unknown variable $src_id. Again, the highlighting shows you the exact location. I can't really help you with this, as I don't know where this variable is coming from. If you are able to fix this yourself I can further assist you with finishing the query.
As for now, the partly corrected query looks like this:
import module namespace functx = "http://www.functx.com" at " http://www.xqueryfunctions.com/xq/functx-1.0-nodoc-2007-01.xq"; declare variable $entryid_prefix as xs:string external; declare variable $src_prefix as xs:string external; declare variable $other_src_prefix as xs:string external;
let $feeds_metadoc := <feed> <entry> <id>1</id> <child src='2' /> <child src='libx.org@gmail.com/core' /> </entry> </feed>
return( copy $feed_copy := $feeds_metadoc modify ( for $entry in $feed_copy/entry return ( for $entry_id in $entry/id where fn:not(fn:contains($entry_id, '/')) return replace value of node $entry_id with concat($entryid_prefix, $entry_id), for $src in $entry/child/@src return ( if (fn:contains(data($src), '/')) then ( let $src_id_new := concat($other_src_prefix, $src_id) return replace value of node $src with $src_id_new ) else ( let $src_data := concat($src_prefix, data($src)) return replace value of node $src with $src_data ) ) ) ) return $feed_copy )
Make sure to consult the BaseX query editor first when you come across issues like this - this will save you a great deal of time as you don't have to wait for our answers ...
Hope I could help! Lukas
On Fri, Sep 23, 2011 at 5:44 AM, Sony Vijay sony.vibh@gmail.com wrote:
Hi,
Given the following xquery: import module namespace functx = "http://www.functx.com" at " http://www.xqueryfunctions.com/xq/functx-1.0-nodoc-2007-01.xq"; declare variable $entryid_prefix as xs:string external; declare variable $src_prefix as xs:string external; declare variable $other_src_prefix as xs:string external;
let $feeds_metadoc :=
<feed> <entry> <id>1</id> <child src='2' /> <child src='libx.org@gmail.com/core' /> </entry> </feed>
return( copy $feed_copy := $feeds_metadoc modify ( for $entry in $feed_copy/entry return ( for $entry_id in $entry/id where fn:not(fn:contains($entry_id, '/')) return replace value of node $entry_id with concat($entryid_prefix, $entry_id) for $src in $entry/child/@src return ( if (fn:contains(data($src), '/')) then ( let $src_id_new := concat($other_srcprefix, $src_id) return replace value of node $src with $src_id_new ) else ( let $src_data := concat($src_prefix, data($src)) return replace value of node $src with $src_data ) ) ) ) return $feed_copy )
Say, the values are passed are - $entryid_prefix = 'http://X/", $src_prefix="http://Y/", and $other_src_prefix="http://Z/". After running the above xqueries by passing these values, I expect the output to be:
<feed> <entry> <id>http://X/1</id> <child src='http://Y/2' /> <child src='http://Z/libx.org@gmail.com/core' /> </entry> </feed>
I am trying to use multiple for statements within the modify statement and this does not work. I see the following error: java.io.IOException: Stopped at line 23, column 10: [XPST0003] Expecting ")", found "f".
I highlighted line 23 for convenience. Please help me fix this.
Thanks, Sony
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