Hi Raymond,

This code will execute, but with an empty result. This is because within the session only db1 is opened and I am querying db2. When explicit opening (session.execute(new Open(db2)); ) it returns the expected value of course. Do you agree that this can be confusing?

I'm not 100% sure how you proceeded. I’ve added another example, which returns "<a/>" as result..

ClientSession session = new ClientSession("localhost", 1984, "admin", "admin"); session.execute(new CreateDB("db1", "<a/>")); session.execute(new CreateDB("db2", "<b/>"));

ClientQuery query = session.query("db:open('db1')"); System.out.println(query.execute()); query.close();

Does this conform to your expectations?

   1) an error that quering db2 while it's not opened in the session
   or
   2) that "db:open('db2')" in the xquery performs implicitly a

session.execute(new Open(db2), so that it automatically switches to db2.

Such a decision could lead to various new questions, because XQuery allows much more databases to be opened in a single query. What would you e.g. expect the following XQuery to do?

for $d in 1 to 5 let $db := db:open($d) return $db//results

..or yet another example:

db:create( "newdb", db:open("olddb") )

Best, Christian ___________________________

I would expect that the xquery in combination with the above code returns

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