Hello all, I have two resources at the same path in a database.
XQUERY db:list("project1") Returns : resultset1.xml
resultset1.xml
The two resources have different contents. However, when I do the following, I get the XML content from the first file.
XQUERY db:open("project1", "resultset1.xml")
What is the way to get the second XML file?
Thanks for your help. Anupam