Hi Dirk,

Thanx for your quick response.

< no, this not a bug. replace() uses regex for its pattern and as the path has {} and [] in them they will be interpreted as regex. >

Hmm, wasn't aware of that, surprising.

< You could write your own replace function or something trivial (but quite limited) like using substring and string-length, e.g.:

substring(path($b), string-length(path($a)) + 1) >

Thnx, for the suggestion. This will do for now.

Greetings, Rob

-----Oorspronkelijk bericht----- Van: basex-talk-bounces@mailman.uni-konstanz.de [mailto:basex-talk-bounces@mailman.uni-konstanz.de] Namens Dirk Kirsten Verzonden: vrijdag 15 augustus 2014 12:11 Aan: basex-talk@mailman.uni-konstanz.de Onderwerp: Re: [basex-talk] relative path between two element in xquery

Hello Rob,

no, this not a bug. replace() uses regex for its pattern and as the path has {} and [] in them they will be interpreted as regex. You could write your own replace function or something trivial (but quite limited) like using substring and string-length, e.g.:

substring(path($b), string-length(path($a)) + 1)

Cheers, Dirk

On 15/08/14 11:55, Rob Stapper wrote:

Hi,

How can I construct the relative path between two elements in an xml-file.

Most probably overlooking the obvious I ended up with the solution below, which, unfortunately, triggers an runtime-error.

My not-working solution:

let $xml :=

<xml>

<A>

  <B/>

</A>

</xml>

let $b := $xml//B

let $a := $xml//A

return replace( string( path( $b))

                         , string( path( $a))

                         , ''

                        )

Two questions:

•      How to retrieve the relative path between two element within a
  

xml-file?

•      Why does the solution above trigger an error? Can it be a bug?
  

(

oops, three questions)

Thnx in advance for the reply,

Rob Stapper

---

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Marc,

I’ve solved the issue in another way but thanks anyway for the code snippet.

Rob.

Van: Marc van Grootel [mailto:marc.van.grootel@gmail.com] Verzonden: vrijdag 15 augustus 2014 12:50 Aan: Rob Stapper CC: BaseX Onderwerp: Re: [basex-talk] relative path between two element in xquery

Hey Rob,

In my lib I have a function that protects all regexp special characters.

Maybe a bit too much heavy machinery for what it does but it works ;-)

I gladly receive improvements.

declare function route:re-escape($string as xs:string)

as xs:string {

let $regexp-chars := ('.','*','+','|','?','(',')','[',']','{','}','^')

return

(: Note that '' and '$' in the fold caused invalid pattern errors therefore put them in separate replace :)

fold-left(

$regexp-chars,

replace(replace($string, '\', '\\'), '$', '\$'),

function($a, $b) {

replace($a, ''||$b, '\'||$b )

}

)

};

--Marc

On Fri, Aug 15, 2014 at 11:55 AM, Rob Stapper r.stapper@lijbrandt.nl wrote:

Hi,

How can I construct the relative path between two elements in an xml-file.

Most probably overlooking the obvious I ended up with the solution below, which, unfortunately, triggers an runtime-error.

My not-working solution:

let $xml :=

<xml>

<A>

<B/>

</A>

</xml>

let $b := $xml//B

let $a := $xml//A

return replace( string( path( $b))

, string( path( $a))

, ''

)

Two questions:

- How to retrieve the relative path between two element within a xml-file?

- Why does the solution above trigger an error? Can it be a bug? ( oops, three questions)

Thnx in advance for the reply,

Rob Stapper

_____

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