Hello all, I have two resources at the same path in a database.
XQUERY db:list("project1") Returns : resultset1.xml
resultset1.xml
The two resources have different contents. However, when I do the following, I get the XML content from the first file.
XQUERY db:open("project1", "resultset1.xml")
What is the way to get the second XML file?
Thanks for your help. Anupam
Correction: XQUERY db:open("project1", "resultset1.xml")
returns contents from not the first one but all files.
But the question remains, if there are two resources at the same path in a database, how to retrieve a specific resource.
Is it even possible?
Thanks, Anupam
Hello all, I've gone thru the documentation but I can't find a way to delete one of many resources located at the same path in a database. So if I have :
% list project1 sample1.xml sample1.xml
Following command deletes both resources at the specified path. % delete sample1.xml
Is there a way to delete a specific resource, not all of them?
Thanks, Anupam
P.S. If you care to know why I need this - it is because I'm getting XML data on a frequent basis that will be stored in the database. Xquery will go in and consolidate the data based on the last few files. I will also need to purge older files. I'm trying to figure out a way to do this. If someone can recommend a better plan of how this might work, I would appreciate it.
Am Freitag, 1. Juni 2012, 05:44:46 schrieb Anupam Bakshi:
Hello all, I've gone thru the documentation but I can't find a way to delete one of many resources located at the same path in a database. So if I have :
% list project1 sample1.xml sample1.xml
Following command deletes both resources at the specified path. % delete sample1.xml
Is there a way to delete a specific resource, not all of them?
Which one of them would you like to delete?
Regards, Dimitar
basex-talk@mailman.uni-konstanz.de
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Anupam Bakshi -
Dimitar Popov